In an examination, the number of those that passed and the number of those were failed are in the ratio 3 : 1, Had 8 more appeared and 6 less passed, the ratio of passes to the failure would have been 2 : 1. Find how many appeared.

In an examination, the number of those who passed and the number of those who failed were in the ratio 25:4. If five more had appeared and the number of failures were 2 less than earlier, the ratio of those passed to failures would be 22:3. The number who appeared at the examination is

In a examination , the number of those who passed and the number of those who faild were in the ratio 25:4 .If five more had appeared and the number of failures were 2 less than earlier , the ratio of students who failed would have been 22:3 . Find the total number who appeared at the examination .

In an examination, the number of those who passed and the number of those who failed were in the ratio 25 : 4. If 5 more had appeared and the number of failures were 2 less than earlier, the ratio of students who passed to the number of students who failed would have been 22 : 3. Find the total number who appeared at the examination.

In an examination, the ratio of passes to failures was 4: 1. Had 30 less appeared and 20 less passed, the ratio of passes to failures would have been 5: 1. Find the number of students who appeared for the examination.

In an examination, the number of those who passed and the number of those who failed were in the ratio 4: 1. If 35 less had appeared and the number of failures were 9 more than earlier, the ratio of students who passed to the number of students who failed would have been 2 : 1. Find the total number who appeared at the examination.

In a certain examination, the number of those who passed was 4 times the number of those who failed. If there had been 35 fewer appeared candidates and 9 more had failed, the ratio of passed and failed candidates would have been 2:1, then the total number of candidates was

From the pair of linear equations in the following problems and find their solutions (if they exist) by elimination method : In an examination the ratio of passes to failures was 4:1. Had 30 less appeared and 20 less passed, the ratio of passes to failures would have been 5:1. How many students appeared for the examination ?

in an examination 96% of the candidate passed and 50 failed. how many candidate appeared?

Find the number of students who took an exam if the ratio of those who passed to those who failed in the exam was 10:3. If 40 more students had taken the exam and 10 less has failed, then the ratio of those who passed to those who failed in the exam would have been 5:1. परीक्षा देने वाले विद्यार्थियों की संख्या ज्ञात करें यदि उस परीक्षा में उत्तीर्ण होने वाले और अनुत्तीर्ण रहने वाले विद्यार्थियों का अनुपात 10:3 था। यदि 40 अन्य विद्यार्थियों ने परीक्षा दी होती और 10 कम छात्र अनुत्तीर्ण हुए होते, तो उस परीक्षा में उत्तीर्ण हुए और अनुत्तीर्ण रहने वाले विद्यार्थियों का अनुपात 5:1 होता।