The initial velocity of a particle is given by `u^(2) = v^(2) - 2gx` where `x` is the distance covered. IF `u = 18 kmh^(-1), g = 1000 cm//s^(2) x = 150 cm` then `v = ......... m//s`

The final velocity fo a particles falling freelly under graavity is given by V^(2) - U^(2) = 2GX WHERE x is the distance covered. IF V = 18 kmph. g = 1000 cm s^(-2), x = 120 cm then u = ...ms^(-1)

If the velocity of a particle is v = At + Bt^2 , where A and B are constant, then the distance travelled by it between 1 s and 2 s is :

If the velocity of a particle is v = At + Bt^2 . where A and B are constants, then the distance travelled by it between 1 s and 2 s is

If the velocity of a particle is v = At + Bt^2 , where A and B are constant, then the distance travelled by it between 1 s and 2 s is :

If the velocity of a particle is v = At + Bt^2 , where A and B are constant, then the distance travelled by it between 1 s and 2 s is :

If the velocity of a particle is v= At+Bt^2, where A and B constants, then the distance travelled by it between 1s and 2s is.

The velocity of a particle is given by v=u_(0) + g t+ 1/2 at^(2) . If its position is x =0 at t=0 , then what is its displacement after t=1 s ?

The velocity of a particle moving on the x-axis is given by v=x^(2)+x , where x is in m and v in m/s. What is its position (in m) when its acceleration is 30m//s^(2) .