An electron and a photon possess the same de Broglie wavelength. If `E_e` and `E_ph` are, respectively, the energies of electron and photon while v and c are their respective velocities, then `(E_e)/(E_(ph))` is equal to

In Q.72,An electron and a photon possess the same de Broglie wavelength. If E e and E p h are, respectively, if the velocity of electron is 25% of the velocity of photon, then (E_e)/(E_(ph)) equals

An electtron and a photon have same wavelength . If p is the moment of electron and E the energy of photons, the magnitude of p//E in S I unit is

An electtron and a photon have same wavelength . If p is the moment of electron and E the energy of photons, the magnitude of p//E in S I unit is

An electron with speed v and a photon with speed c have the same de-Broglic wavelength. If the kinetic energy and momentum of electron is E_(e) and P_(e) and that of photon is E_(ph) and P_(ph) respectively, then correct statement is -

An electron of mass m and a photon have same energy E. The ratio of de Broglie wavelength associated with them is

If E_1, E_2 and E_3 represent respectively the kinetic energies of an electron, an alpha - particle and a proton each having same de-Broglie wavelength, then