The normal chord of a parabola `y^2= 4ax` at the point `P(x_1, x_1)` subtends a right angle at the

Statement 1: Normal chord drawn at the point (8,8) of the parabola y^(2)=8x subtends a right angle at the vertex of the parabola.Statement 2: Every chord of the parabola y^(2)=4ax passing through the point (4a,0) subtends a right angle at the vertex of the parabola.

Statement 1: Normal chord drawn at the point (8, 8) of the parabola y^2=8x subtends a right angle at the vertex of the parabola. Statement 2: Every chord of the parabola y^2=4a x passing through the point (4a ,0) subtends a right angle at the vertex of the parabola.

If a normal chord of a puint on the parabola y^(2) = 4ax , subtends a right angle at the vertex, then t =

The normal chord of the parabola y^(2)=4ax subtends a right angle at the focus.Then the end point of the chord is

The normal chord of the parabola y^(2)=4ax subtends a right angle at the vertex.Then the length of chord is

If a normal chord of a parabola y^(2) = 4ax subtends a right angle at the origin, then the slope of that normal chord is

If the normal chord drawn at the point P(t) to the parabola y^(2) = 4ax subtends a right angle at the focus, then show that , = pm2