In atension from state `n` to a state of excitation energy `10.19 eV`, hydrogen atom emits a `4890 Å` photon. Etermine the binding energy of the initial state.

In atension of state n from a state of excitation energy given is 10.19 eV , hydrogen atom emits a photon with wavelength 4890 Å . Determine the binding energy of the initial state.

A hydrogen atom in a state of binding energy 0.85 eV makes a transtition to a state of excitation energy of 10.2 eV. (i) What is the initial state of hydrogen atom? (ii) What is the final state of hydrogen atom ? (iii) What is the wavelength of the photon emitted ?

A hydrogen atom in a state of binding energy 0.55eV make a trasisition to a state of excitation energy of 10.2 eV (i) what is the initial state of hydrogen atom? (ii) what is the final state of hydrogen atom? (iii) what is the wavelength of the photon emitted?

A hydrogen atom in a state having a binding energy of 0.85 eV makes transition to a state with excitation energy 10.2 eV. The quantum number n of the upper and the lower energy states are

A hydrogen atom is in a state of ionization energy 0.85 eV. If it makes a transition to the ground state, what is the energy of the emitted photon.

The ratio of the binding energies of the hydrogen atom in the first and the second excited states is

A hydrogen atom in a state of binding energy 0.85 eV makes a transition to a state of excitation energy of 10.2 eV . Find the energy and wavelength of photon emitted.