`cos1 8^(@)-sin1 8^(@)=`

(cos8^(@)+sin8^(@))/(cos8^(@)-sin8^(@))=tan53^(@)

2sin ^ (2) (8 (1 ^ (@)) / (2)) + 4cos16 ^ (@) sin (7 (1 ^ (@)) / (2)) sin (8 (1 ^ (@)) / (2)) + cos32 ^ (@) =

sin ^ (8) A-cos ^ (8) A = (sin ^ (2) A-cos ^ (2) A) (1-2sin ^ (2) A cos ^ (2) A)

(cos8^@-sin8^@)/(cos8^@+sin8^@) is equal to

2sin^(2)(8(1^(0))/(2))+4 cos 16^(0) sin(7(1^(0))/(2)) sin (8(1^(0))/(2))+cos32^(0)=

(sin2^(@)+sin4^(@)+sin6^(@)+sin8^(@))/(cos1^(@)*cos2^(@)*cos5^(@))=

int (cos^(8)x-sin^(8)x)/(1-2 cos^(2)sin^(2)x)dx=

Show that: sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A cos^(2)A)

Show that: sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A*cos^(2)A)