In the given fig, AB is the diameter of the circle with centre O. The point C, D and E are on the circle such that AC = CD = DE = EB. Find `angleEBA`.

In the given fig,AB is the diameter of the circle with centre O.The point C,D and E are on the circle such that AC=CD=DE=EB Find /_EBA.

In the given Fig., AC is diameter of the circle with centre O and A is point of contact, then find x.

If Fig , AOB is diameter of a circle with centre O and AC is a tangent to the circle at A . If angle BOC = 130^@ , then find angleACO .

In the figure given below,AD is a diameter of a circle with centre O.If AB II CD,prove that AB=CD

In the given figure, AB is the diameter of the circle centered at O. If angle COA = 60^(@) , AB = 2r , AC = d . and CD = l, then l is equal to

In the given figure, AB is the diameter of the circle, centered at O. If angle COA =60^(@), AB=2r, Ac=d and CD=l, then l is equal to

In the given figure, AB is the diameter of the circle, centered at O. If angle COA =60^(@), AB=2r, Ac=d and CD=l, then l is equal to

In the given figure, AB is the diameter of the circle, centered at O. If angle COA =60^(@), AB=2r, Ac=d and CD=l, then l is equal to

In the figure, O is the centre of the circle . Seg AB is the diameter at the point C on the circle the tangent CD is drawn. Line BD is a tangent to the circle at point B. Show that seg OD || chord AC.