011(JP)]quad .8.cos2x cos4x cos6x

cos2x-cos8x+cos6x=1

1+ cos 2x+ cos4x + cos 6x=

int cos2x*cos4x*cos6xdx

int cos2x*cos4x*cos6x dx

If g(x)=cos x cos2x cos4x cos8x then g'((pi)/(4))=

If f(x)=cos x cos2x cos4x cos8x cos16x then

The equation 8cosx cos2x cos4x = (sin6x)/(sinx) has a solution given by :

The value of int_( sin )x cos x cos2x cos4x cos8x cos16x)dx is int(sin x cos x cos2x cos4x cos8x cos16x)dx is equal to

If f(x)=cos x cos2x cos4x cos(8x)*cos16x then find f'((pi)/(4))

If f(x)=cos x cos2x cos4x cos8x cos16x then f'((pi)/(4)) equals