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the number of moles of Cr(2)O(7)^(2) nee...

the number of moles of `Cr_(2)O_(7)^(2)` needed to oxidise `0.136` equivalent of `N_(2)H_(5)` through the reaction:
`N_(2)H_(5) + Cr_(2)O_(7)^(2-) rarr N_(2) + Cr^(3) + H_(2)O` is:

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What is equivalent mass of (NH2_4)_2Cr_2O_7 in the change (NH_(4))_(2)Cr_(2)O_(7) rarr N_(2) + Cr_(2)O_3 + 4H_(2)O ?

Equivalent weight of (NH_(4))_(2)Cr_(2)O_(7) in the changes is: (NH)_(4)Cr_(2)O_(7)rarrN_(2)+Cr_(2)O_(3)+4H_(2)O

In the reaction, Cr_(2)O_(7)^(2-)+H_(2)O to 2CrO_(4)^(2-)+2H^(+) Cr undergoes