" 3) "-4/4(1+2i)/(2+i)=gamma(cos theta+i sin theta)(v)/(e)sqrt(d)

If (1+2i)/(2+i)=r(cos theta+i sin theta) then

If (1+2i)/(2+i)=r(cos theta+i sin theta) then

I : If sin((pi)/(4)cot theta)=cos ((pi)/(4)tan theta) then theta = n pi+pi//4, n in Z II : If tan ((pi)/(2)sin theta)=cot((pi)/(2)cos theta) then sin (theta + (pi)/(4))= pm (1)/(sqrt(2))

If ((4i^(3)-i)/(2i+1))^(2)=r(cos theta+isin theta) , then cos theta+sin theta is equal to (where, i^(2)=-1 )

If ((4i^(3)-i)/(2i+1))^(2)=r(cos theta+isin theta) , then cos theta+sin theta is equal to (where, i^(2)=-1 )

((cos theta+i sin theta)/(sin theta+i cos theta))^(4)=

We express ((cos 2theta -i sin 2theta)^(4) (cos 4theta + i sin 4 theta)^(-5))/((cos 3theta + i sin 3theta)^(-2) (cos 3theta -i sin 3theta)^(-9)) in the form of x+iy , we get

What is the modulus of the complex number (cos theta+i sin theta)/(cos theta-i sin theta) where i=sqrt(-1) ?