[" A "5096" of "CO_(2)" converts to "CO" at the following equilibrium: "],[qquad (1)/(2)C(s)+(1)/(2)CO_(2)(g)rightleftharpoons Co(g)],[" and the equilibrium pressure is "12atm." Calculate "K_(p)]

In the reaction C(s)+CO_(2)(g) hArr 2CO(g) , the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(p) .

In the reaction C(s)+CO_(2)(g) hArr 2CO(g) , the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(p) .

In the reaction C(s)+CO_(2)(g) hArr 2CO(g) , the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(p) .

In the reaction C(s) + CO_2(g) hArr 2CO(g) the equilibrium pressure is 12 atm. If 50% OF CO_2 reacts. Calculate the K_P for the change:

A vessel at 1000K contains CO_(2)(g) at 2 atm pressure. When graphite is added the following equilibrium is established. CO_(2)(g)+C(s) hArr 2CO(g) the toal pressure at equilibrium is 3 atm. The value of K_(p) is

A vessel at 1000K contains CO_(2)(g) at 2 atm pressure. When graphite is added the following equilibrium is established. CO_(2)(g)+C(s) hArr 2CO(g) the toal pressure at equilibrium is 3 atm. The value of K_(p) is

For the reaction, 0.5 C(s)+0.5CO_(2)(g) hArr CO(g) the equilibrium pressure is 12 atm. If CO_(2) conversion is 50%, the value of K_(p) , in atom is