((cos theta+i sin theta)^(4))/((sin theta+i cos theta)^(5))" is equal to "

((cos theta+i sin theta)/(sin theta+i cos theta))^(4)=

([cos theta+i sin theta)/(sin theta+i cos theta))^(4)=?

"(cos theta+i sin theta)^(6)(cos theta-i sin theta)^(-3)

If theta varepsilon R and i=sqrt(-1), then ((1+sin theta+i cos theta)/(1+sin theta-i cos theta))^(n) is equal to

((cos theta + i sin theta) / (sin theta + i cos theta)) ^ (4) = cos8 theta + i sin8 theta

(cos theta + i sin theta)^3 xx (cos theta-i sin theta)^4=

If theta in the first quadrant and 5 tan theta =4 " then " ( 5 sin theta - 3 sin theta)/( sin theta + 2 cos theta) is equal to

(i) |(cos theta,-sin theta),(sin theta,cos theta)|

(1+cos theta+i sin theta)^(10)+(1+cos theta-i sin theta)^(10)=