" (iii) "int_(0)^((pi)/(2))[2log sin x-log sin2x]dx

int_(0)^((pi)/(2))(2log cos x-log sin2x)dx

int_(0)^((pi)/(2))log(sin x)dx

int_(0)^((pi)/(2))log(sin2x)dx

int_(0)^(pi//2) (2logsin x - log sin 2x) dx=

By using the properties of definite integrals, evaluate the integrals int_(0)^((pi)/(2))(2log sin x-log sin2x)dx

int_(0)^((pi)/(2))cos2x log sin xdx

int_(0)^(pi//2) log sin x dx =

The value of int_(0)^(pi//2) (2log sin x-log sin 2x)dx , is

The value of int_(0)^(pi//2) (2log sin x-log sin 2x)dx , is