[" Calculate the height of the potential barrier for a head on collision of two deuterons.(Hint: The "],[" height of the potential barrier is given by the Coulomb repulsion between the two deuterons "],[" when they just touch each other.Assume that they can be taken as hard spheres of radius "2.0fm" .) "],[" What is rectifier? Explain "F" ull were cont; "f" ."]

Calculate the height of potential barrier for a head on collision of two deuterons. The effective radius of deuteron can be taken to be 2fm. Note that height of potential barrier is given by the Coulomb repulsion between two deuterons when they just touch each other.

Calculate the height of potential barrier for a head on collision of two deuterons. The effective radius of deuteron can be taken to be 2fm. Note that height of potential barrier is given by the Coulomb repulsion between two deuterons when they just touch eachother.

Calculate the height of the Coulomb barrier for the head on collision of two deuterons, with effective radius 2.1 fm.

Assume a proton is a sphere of radius R~~1 fm. Two protons are fired at each other with the same kinetic energy. K a. What must K be if the paticles are brought to rest by their mutual Coulomb repulsion when they are just touching each other? We can take this value of K as a representative measure of the height of the Colulomb barrier.

Consider the D–T reaction (deuterium–tritium fusion) ""_(1)^(2)H + ""_(1)^(3)H to ""_(2)^(4)He + n (a) Calculate the energy released in MeV in this reaction from the data: m (""_(1)^(2)H) = 2.014102u m(""_1^(3)H) = 3.016049 u (b) Consider the radius of both deuterium and tritium to be pproximately 2.0 fm. What is the kinetic energy needed to overcome the coulomb repulsion between the two nuclei? To what temperature must the gas be heated to initiate the reaction? (Hint: Kinetic energy required for one fusion event =average thermal kinetic energy available with the interacting particles = 2(3kT/2), k = Boltzman’s constant, T = absolute temperature.)

Consider the D–T reaction (deuterium–tritium fusion) ""_(1)^(2)H + ""_(1)^(3)H to ""_(2)^(4)He + n (a) Calculate the energy released in MeV in this reaction from the data: m (""_(1)^(2)H) = 2.014102u m(""_1^(3)H) = 3.016049 u (b) Consider the radius of both deuterium and tritium to be pproximately 2.0 fm. What is the kinetic energy needed to overcome the coulomb repulsion between the two nuclei? To what temperature must the gas be heated to initiate the reaction? (Hint: Kinetic energy required for one fusion event =average thermal kinetic energy available with the interacting particles = 2(3kT/2), k = Boltzman’s constant, T = absolute temperature.)