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[" Why is "Cr^(2+)" reducing and "Mn^(3+...

[" Why is "Cr^(2+)" reducing and "Mn^(3+)" oxidising when both have "d^(4)" configuration."],[" Cretic reduciotes and Mn" oxidising when both have "d" " configuration."]

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Why is Cr^(2+) acts as reductant and Mn^(3+) as oxidant eventhough both have d^4 configuration ?

Why is Cr^(2+) reducing and Mn^(3+) oxidizing even though both have the same d^(4) electronic configuration.

(A) Cr^(2+) is reducing while Mn^(3+) is oxidizing when both have d^4 configuration. (R) Configuration of Cr^(2+) changes from d^3 to d^4

The ion Cr^(2+) is redusing agent while that of Mn^(3+) is an oxidising agent though both have 3d^(4) configuration. This is because

Assertion : Cr^(2+) is reducing and Mn^(3+) is oxidising. Reason : Cr^(2+) and Mn^(3+) have d^4 configuration.

Assertion : Cr^(2+) is reducing and Mn^(3+) is oxidising. Reason : Cr^(2+) and Mn^(3+) have d^4 configuration.

Explain why Cr^(2+) behaves reducing while Mn^(3+) oxidising through both are havign d^9 configuration. What is interstetial compound?