The solubility product of AgCl is `4.0 xx 10^(-10)` at 298 K . The solubility of AgCl in 0.04 M Ca `Cl_(2)` will be

The solubility product of silver chloride is 1.8 xx 10^(-10) at 298 K. The solubility of AgCl in 0.01 M HCl solution in mol // dm^(3) is

The solubility product of AgCl is 1.8xx10^(-10) at 18^(@)C . The solubility of AgCl in 0.1 M solution of sodium chloride would be

The solubility product of AgCl is 2.8xx10^(-10) at 298 K. Calculate the solubility of AgCl in (i) pure water (ii) 0.1M AgNO_(3) solution, and (iii) 0.1M HCl solution.

The solubility product of AgCl is 1.56xx10^(-10) find solubility in g/ltr

The solubility product of AgCl is 1.56xx10^(-10) find solubility in g/ltr