The value of `lim_((1)->0) P A` is

The value of lim_((1)rarr0)PA is

The value of lim_( x -> 0 ) ( ( x + 1 )^5 - 1 ) / x

If the value of lim_(x->0)( ((3/ x)+1)/((3/x)-1))^(1/x) can be expressed in the form of e^(p/q), where p and q are relative prime then find the value of (p+q) .

The value of : lim_(x to 0) (cos x)^(1/x) is

The value of lim_(x to 0) ((1)/(x) - cot x) equals

The value of lim_(x to 0) ((1)/(x) - cot x) equals

The value of lim_(x rarr1)(x^(p+1)-px+p)/((x-1)^(2)) equals

The value of lim_(xrarr 0) (1+sinx)^2 , is

The value of lim_(xrarr0)(1-cosx)/x is