[" Question "23:],[" If the line "x=b" bisects the area under the curve "y=(1)/(x^(2)),1<=x<=9," then "b" is equal to "],[[" (A) "(4)/(9)," (B) "(9)/(5)," (C) "(5)/(9)," (D) "(9)/(4)]]

If the line x=a bisects the area under the curve y=(1)/(x^(2)), 1 le x le 9 , then a is equal to

If the line x=a bisects the area under the curve y=(1)/(x^(2)), 1 le x le 9 , then a is equal to

Find the area between the line y=x+1 and the curve y=x^(2)-1

The line y=mx bisects the area enclosed by the curve y=1+4x-x^(2) and the lines x=0,x=(3)/(2) and y=0. Then the value of m is (A) (13)/(6) (B) (6)/(13)(C)(3)/(2) (D) 4

If the line y = mx bisects the area enclosed by the lines x = 0, y = 0, x = (3)/(2) and the curve y = 1 + 4x - x^(2) , then 12 m is equal to _________.

(i) Make a rough sketch of the function y = x^(2) and shade the region under the curve, x-axis and the ordinates at x = 1 and x = 3. (ii) Find the area under the curve y = x^(2) above.

If A is the area of the region bounded by the curve y= sqrt(3x + 4) , x- axis and the lines x=-1 and x=4 and B is the area bounded by the curve y^(2)= 3x + 4 and the lines x=-1 and x=4 , then the value of A : B is-

What is the area under the curve y=|x|+|x-1| between x=0 and x=1?

The line y=m x bisects the area enclosed by the curve y=1+4x-x^2 and the lines x=0,x=3/2 and y=0. Then the value of m is