A spherical ball of salt is dissolving in water in such a manner that the rate of decrease of volume at any instant is proportional to the surface. Prove that the radius is decreasing at a constant rate.

A spherical ball of salt is dissolving in water in such a manner that the rate of decrease of the volume at any instant is propotional to the surface. Prove that the radius is decreasing at a constant rate. Hint for solution : Take volume V and curve surface are S of spherical ball. Calculate by taking (dV)/(dt)alpha S .

A spherical ball of salt is dissovlging water in such a manner that the rate of decrease of the volume at any instant is proportional to the surface. Prove that the radis is decreasing at a constant rate.

The rate constant of any reaction is proportional to the concentration of the reactants.

The radius of a sphere is decreasing at the rate of 3 cm per second. Obtain the rate of decrease of the surface area when the radius is 18 cm.

If the volume of a sphere is increasing at a constant rate, then the rate at which its radius is increasing, is

Suppose that water is emptied from a spherical tank of radius 10 cm. If the depth of the water in the tank is 4 cm and is decreasing at the rate of 2 cm/sec, then the radius of the top surface of water is decreasing at the rate of

Suppose that water is emptied from a spherical tank of radius 10 cm. If the depth of the water in the tank is 4 cm and is decreasing at the rate of 2 cm/sec, then the radius of the top surface of water is decreasing at the rate of