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[" 3."20mL" of "0.1MH(2)SO(4)" solution ...

[" 3."20mL" of "0.1MH_(2)SO_(4)" solution is added "],[30mL" of "0.2MNH_(4)OH" solution.The pH "],[" the resulatant mixture is "IpK_(b)" if "NH_(4)OH=4" ."],[[" 1) "9.4," 2) "5.02," 3) "9.0," 4) "5.2]]

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20mL of 0.1M(H_(2)SO_(4)) solution is added to 30mL of 0.2M(NH_(4)OH) soulution. The ._(p)H of the resultant mixture is : [._(p)k_(b) " of " NH_(4)OH=4.7] .

20mL of 0.1M(H_(2)SO_(4)) solution is added to 30mL of 0.2M(NH_(4)OH) soulution. The ._(p)H of the resultant mixture is : [(p)k_(b) " of " NH_(4)OH=4.7] .

20 mL of 0.1 M H_2SO_4 solution is added to 30 mL of 0.2 M NH_4OH solution. The pH of the resultant mixture is : [ pK_b of NH_4OH =4.7]

Amount of (NH_(4))_(2)SO_(4) which must be added to 50mL of 0.2 M NH_(4)OH solution to yield a solution of pH 9.26 is ( pK_(b) of NH_(4)OH=4.74 )

A solution contains 60 mL of 0.1 M NH_(4)OH and 30 mL of 0.1 MHCl . The P^(H) of the resulting mixture is (Given K_(b) of NH_(4)OH = 1.8 xx 10^(-5) , 1.8 = 0.2553 )

When 20 ml of 0.1 MNH_(4)OH are added to 20 ml of MNH_(4)Cl solution, the pH of the buffer formed is 8.2. What is the pK_(b) of NH_(4)OH ?

10 ml of M/10 NH_(4)OH is mixed with 4ml of M/10H_(2)SO_(4) solution. The pH of the resulting solution is (pK_(b)NH_(4)OH=4.76), (log2=0.3) .