A nucleus X initially at rest, undergoes alpha decay according to the equation
`_Z^232Xrarr_90^AY+alpha`
What fraction of the total energy released in the decay will be the kinetic energy of the alpha particle?

A nucleus X, initially at rest, undergoes alpha-decay according to the equation. _92^AXrarr_Z^228Y+alpha (a) Find the values of A and Z in the above process. (b) The alpha particle produced in the above process is found in move in a circular track of during the process and the binding energy of the parent nucleus X. Given that m(Y)=228.03u , m( _0^1n)=1.009u m( _2^4He)=4.003u , m( _1^1H)=1.008u

A nucleus X, initially at rest, undergoes alpha-decay according to the equation. _92^AXrarr_Z^228Y+alpha (a) Find the values of A and Z in the above process. (b) The alpha particle produced in the above process is found in move in a circular track of during the process and the binding energy of the parent nucleus X. Given that m(Y)=228.03u , m( _0^1n)=1.009u m( _2^4He)=4.003u , m( _1^1H)=1.008u

A nucleus of mass number 220 decays by alpha decay. The energy released in the reation is 5 MeV. The kinetic energy of an alpha- particle is

A stationary ._(82)^(200)Pb nucleus emits an alpha -particle with kinetic energy T_(alpha) = 5.77 MeV . Find the recoil velocity of a daughter nucleus. What fraction of the total energy liberated in this decay is accounted for by the recoil energy of daughter nucleus ?

A nucleus with mass number 220 initially at rest emits an alpha -particle. If the Q value of the reaction is 5.5MeV, calculate the kinetic energy of the alpha -particle.

During alpha-decay , a nucleus decays by emitting an alpha -particle ( a helium nucleus ._2He^4 ) according to the equation ._Z^AX to ._(Z-2)^(A-4)Y+._2^4He+Q In this process, the energy released Q is shared by the emitted alpha -particle and daughter nucleus in the form of kinetic energy . The energy Q is divided in a definite ratio among the alpha -particle and the daughter nucleus . A nucleus that decays spontaneously by emitting an electron or a positron is said to undergo beta -decay .This process also involves a release of definite energy . Initially, the beta -decay was represented as ._Z^AX to ._(Z+1)^AY + e^(-)"(electron)"+Q According to this reaction, the energy released during each decay must be divided in definite ratio by the emitted e' ( beta -particle) and the daughter nucleus. While , in alpha decay, it has been found that every emitted alpha -particle has the same sharply defined kinetic energy. It is not so in case of beta -decay . The energy of emitted electrons or positrons is found to vary between zero to a certain maximum value. Wolfgang Pauli first suggested the existence of neutrinoes in 1930. He suggested that during beta -decay, a third particle is also emitted. It shares energy with the emitted beta particles and thus accounts for the energy distribution. The beta particles (positron) are emitted with different kinetic energies because