[26ymx-ny=m^(2)+n^(2)],[x+y=2m]

Solve the following system of equations by method of cross-multiplication: mx-ny=m^(2)+n^(2),quad x+y=2m

solve the following pair using cross multiplication method mx+ny=m^(2)+n^(2) and x+y=2m

Solve for x and y : mx- ny = m^(2) + n^(2) " " x - y = 2n

Solve the following system of equations by method of cross-multiplication: m x-n y=m^2+n^2,\ \ \ \ x+y=2m

Solve the following simultaneous equations for x and y : m(x+y)+n(x-y)-(m^(2)+mn+n^(2))=0, n(x+y)+m(x-y)-(m^(2)-mn+n^(2))=0

The area of the quadrilateral formed by two pairs of lines l^(2) x^(2)-m^(2) y^(2)-n(l x+m y)=0 and l^(2) x^(2)-m^(2) y^(2)-n(L x-m y)=0 is

If x cos A + y sin A = m and x sin A - y cos A = n, then prove that : x^(2) + y^(2) = m^(2) + n^(2)

If m =! n and (m + n)^(-1) (m^(-1) + n^(-1)) = m^(x) n^(y) , show that : x + y + 2 = 0.