If `(2+i)r^(-1)={4i+(1+i)^2}(costheta+isintheta)` then value of r is

(1+costheta-isintheta)^4 =

If (1+2i)/(2+i)=r(costheta+isintheta) then

x+iy=1/(1+costheta+isintheta),"then "4x^2=

If sqrt(3)-i=r(costheta+isintheta) , then r= . . . .

Express 1/(1-costheta+2isintheta) in the form x+i y .

Express 1/(1-costheta+2isintheta) in the form x+i y .

Express 1/(1-costheta+2isintheta) in the form x+i y .

If e^(itheta)=costheta+isintheta, find the value of |[1,e^(ipi//3),e^(ipi//4)],[e^(-ipi//3),1,e^(i2pi//3)],[e^(-ipi//4),e^(-i2pi//3),1]|

If e^(itheta)=costheta+isintheta, find the value of |[1,e^(ipi//3),e^(ipi//4)],[e^(-ipi//3),1,e^(i2pi//3)],[e^(-ipi//4),e^(-i2pi//3),1]|

Express i in the form r(costheta+isintheta)