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[" 103."|[a^(2)+x^(2),ab,ca],[ab,b^(2)+x...

[" 103."|[a^(2)+x^(2),ab,ca],[ab,b^(2)+x^(2),bc],[ca,bc,c^(2)+x^(2)]|" is divisor of "],[[ca,bc,c^(2)+x^(2)]|[" is divisor of "],[c^(2)+x^(2)]],[[" (a) "a^(2)," (b) "b^(2)]]

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|(a,b,c),(a^(2),b^(2),c^(2)),(bc,ca,ab)|=

|{:(a^2,ab,ac),(ab,b^2,bc),(ca,bc,c^2):}|= ?

|[bc,ca,ab],[(b+c)^(2),(c+a)^(2),(a+b)^(2)],[a^(2),b^(2)c^(2)]|

|((b+c)^(2),a^(2),bc),((c+a)^(2),b^(2),ca),((a+b)^(2),c^(2),ab)|=

Prove that |[(a+b)^(2),ca,bc],[ca,(b+c)^(2),ab],[bc,ab,(c+a)^(2)]|=2abc(a+b+c)^(3)

det[[bc-a^(2),ca-b^(2),ab-c^(2)ca-b^(2),ab-c^(2),bc-a^(2)ab-c^(2),bc-a^(2),ca-b^(2)]]=det[[a,b,cb,c,ac,a,b]]^(2)

Prove that [[a^2,bc,c^2+ca],[a^2+ab,b^2,ca],[ab,b^2+bc,c^2]]= 4a^2b^2c^2 .

|[bc-a^2,ca-b^2,ab-c^2],[ca-b^2,ab-c^2,bc-a^2],[ab-c^2,bc-a^2,ca-b^2]|=|[a,b,c],[b,c,a],[c,a,b]|^2