Tangents PA and PB are drawn to a circle with point P outside the circle, line joining P and centre intersect chord AB at M then, Prove that `/_OPA = /_OAM`

From an external point P, two tangents, PA and PB are drawn to a circle with centre 0. At one point E on the circle tangent is drawn which intersects PA and PB at C and D, respectively. If PA=10 cm, find the perimeter of the triangle PCD.

From an external point P, two tangents, PA and PB are drawn to a circle with centre 0. At one point E on the circle tangent is drawn which intersects PA and PB at C and D, respectively. If PA=10 cm, find the perimeter of the triangle PCD.

Two tangents PA and PB are drawn to a circle with centre O from an external point P. Prove that angle APB = 2 angle OAB

Two tangents PA and PB are drawn to circle with centre O from an external point P. Prove that angleAPB= 2angleOAB

PA and PB are tangents to a circle with centre O, from a point P outside the circle and A and B are points on the circle. If /_ APB = 30^(@) , then /_ OAB is equal to :

PA and PB are tangents to a circle with centre 0, from a point P outside the circle, and A and B are point on the circle. If angleAPB = 30^(@) , then angleOAB is equal to:

PA and PB are two tangents to a circle with centre O, from a point P outside the circle . A and B are point P outside the circle . A and B are point on the circle . If angle PAB = 47^(@) , then angle OAB is equal to :

PA and PB are two tangents to a circle with centre O, from a point P outside the circle. A and B are points on the circle. If angleAPB =100^(@) , then OAB is equal to: