The parabola `y^2 = 2x` divides the circle `x^2 + y^2 = 8` in two parts. Then, the ratio of the areas of these parts is

The parabola y= (1)/(2)x^(2) divides the circle x^(2) + y^(2)=8 into two parts find the area of each part.

Let f(x) be a polynomial of degree three such that the curve y=f(x) has relative extremes at x=+-(2)/(sqrt(3)) and passes through (0,0) and (1,-1) dividing the circle x^(2)+y^(2)=4 in two parts the ratio of the areas of two parts

The area enclosed by the circle x^2+(y+2)^2=16 is divided into two parts by the x-axis. Find by integration, the area of the smaller part.

The area enclosed by the circle x^2+(y+2)^2=16 is divided into two parts by the x-axis. Find by integration, the area of the smaller part.

The circle x^(2) + y^(2)=8 is divided into two parts by the parabola 2y=x^(2) . Find the area of both the parts.

The circle x^(2) + y^(2)=8 is divided into two parts by the parabola 2y=x^(2) . Find the area of both the parts.

The area of the circle x^2+y^2 = 8x , lying above x-axis and interior to the parabola y^2= 4x is

The circle x^(2)+y^(2) =4a^(2) is divided into two parts by the line x =(3a)/(2). Find the ratio of areas of these two parts.

The circle x^(2)+y^(2) =4a^(2) is divided into two parts by the line x =(3a)/(2). Find the ratio of areas of these two parts.