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The area bounded by the lines y = 2, x =...

The area bounded by the lines `y = 2, x =1, x = a` and the curve `y = f(x),` which cuts the last two lines above first line for all `a gt= 1,` is equal to `2/3[(2a)^(3//2)-3a+3-2sqrt2],` then `f(x)=`

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