The value of `a` for the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1,(a > b),` if the extremities of the latus rectum of the ellipse having positive ordinates lie on the parabola `x^2=2(y-2)` is ___

Ellipse (x^2)/(a^2)+(y^2)/(b^2)=1,(a > b), If the extremities of the latus rectum of the with positive ordinates lie on the parabola x^(2) = 3(y + 3) , then length of the transverse axis of ellipse is

The latus rectum of the ellipse 16x^2+y^2=16 is:

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

The equation of the normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at the end of the latus rectum in the first quadrant is