Fig. 18.173 (a) 6 V (5) The given infinite , (b) 4V (c) zero (d) 2 V infinite grid consists of hexagonal cells of six fors each of resistance R. Then Ri, Fig. 18.174 wiwerod wolod woda entito un cos RCHIVES

The given infinite grid consists of hexagonal cells of six resistors each of resistance R. then R_(12)

The given infinite grid consists of hexagonal cells of six resistors each of resistance R. then R_(12)

The given infinite grid consists of hexagonal cell of six resistor each of resistance R . Then R_(12) is equal to

The circuit in Fig. shows two cells connected in opposition to each other. Cell E_(1) is of emf 6V and internal resistance 2Omega, the cell E_(2) is of emf 4 V sand internal resistance 8omega . Find the potential difference between the points A and B .

The circuit in Fig. shows two cells connected in opposition to each other. Cell E_(1) is of emf 6V and internal resistance 2Omega, the cell E_(2) is of emf 4 V sand internal resistance 8omega . Find the potential difference between the points A and B .

In Fig. 26-18a, a 9.00 V battery is connected to a resistive strip that consists of three sections with the same cross-sectional areas but different conductivities. Figure 26-18h gives the electric potential V(x) versus position x along the strip. The horizontal scale is set by x= 8.00 mm. Section 3 has conductivity 4.00 xx 10^(7) (Omega.m)^(-1) . What is the conductivity of section (a) 1 and (b) 2 ? a.

In the given circuit, an ideal voltmeter connected across the 10 Omega resistance reads 2 V.The internal resistance r, of each cell is : a) 1Ω b) 0.5Ω c) 1.5Ω d) 0Ω

Let V and I respresent, respectively, the readings of the voltmeter and ammetre shows in Fig. 6.34 , and let R_(V) and R_(V) be their equivalent resistances. Because of the resistances of the meters, the resistnce R is not simply equal to V//I . (a) When the circuit is connected as shows in Fig. 6.34 (a), shows that R = (V)/(I) - R_(A) Explain why the true resistance R is always less than V//I . (b) When the connections are as shows in Fig. 6.34 (b) Show that R = (V)/(I - (V//R_(V))) Explain why the true resistance R is always greater than V//I . (c ) Show that the power delivered to the resistor in part (i) is IV - I^(2) R_(A) and that in part (ii) is IV - (V^(2)//R_(V))

Let V and I respresent, respectively, the readings of the voltmeter and ammetre shows in Fig. 6.34 , and let R_(V) and R_(V) be their equivalent resistances. Because of the resistances of the meters, the resistnce R is not simply equal to V//I . (a) When the circuit is connected as shows in Fig. 6.34 (a), shows that R = (V)/(I) - R_(A) Explain why the true resistance R is always less than V//I . (b) When the connections are as shows in Fig. 6.34 (b) Show that R = (V)/(I - (V//R_(V))) Explain why the true resistance R is always greater than V//I . (c ) Show that the power delivered to the resistor in part (i) is IV - I^(2) R_(A) and that in part (ii) is IV - (V^(2)//R_(V))