`A B C P` is a quadrant of a circle of radius 14 cm. With `A C` as diameter, a semi-circle is drawn. Find the area of the shaded portion.

BCP is a quadrant of a circle of radius 14cm. With AC as diameter,a semi-circle is drawn. Find the area of the shaded portion.

ABCP is a quadrant of a circle of radius 14cm. With AC as diameter,a semi-circle is drawn.Find the area of the shaded portion.

ABCP is a quadrant of a circle of radius 14 cm. with AC as diameter, a semicircle is drawn. Find the area of the shaded portion

ABCP is a quadrant of a circle of radius 14 cm. with AC as diameter, a semicircle is drawn. Find the area of the shaded portion

In Fig. 12.64, ABCP is a quadrant of a circle of radius 20 cm. With AC as diameter, a semi-cirde is drawn. Find the area of the shaded portion.

ABCP is one-fourth of the circle whose radiusis 14 cm. Taking AC is diameter a semi circle is drawn. Find the area of shaded portion.

AOBPA is a quadrant of a circle of radius 14cm . A semi-circle with AB as diameter is drawn. Find the area of the shaded point. ( pi=22/7 )

In fig., ABC is a quadrant of a circle of radius 14 cm and a semi circle is drawn with BC as diameter. Find the area of the shaded region.

In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.