Equation of motion in the same direction is given by `y_1=Asin(omegat-kx)`,`y_2=Asin(omegat-kx-theta)`. The amplitude of the medium particle will be

Equation of motion in the same direction is given by y_(1) =A sin (omega t - kx), y_(2) = A sin ( omega t - kx- theta ) . The amplitude of the medium particle will be

Equation of motion in the same direction is given by y_(1) =A sin (omega t - kx), y_(2) = A sin ( omega t - kx- theta ) . The amplitude of the medium particle will be

Equation of motion in the same direction are given by ltbygt y_(1)=2a sin (omega t-kx) and y_(2)=2a sin (omega t-kx - theta ) The amplitude of the medium particle will be

Equation of motion in the same direction are given by ltbygt y_(1)=2a sin (omega t-kx) and y_(2)=2a sin (omega t-kx - theta ) The amplitude of the medium particle will be

Two waves are given as y_1=3A cos (omegat-kx) and y_2=A cos (3omegat-3kx) . Amplitude of resultant wave will be ____

Two waves are given as y_1=3A cos (omegat-kx) and y_2=A cos (3omegat-3kx) . Amplitude of resultant wave will be ____

The dimension of omega in the expression y= Asin (omegat-kx) is

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -