[a^(2)+a^(2)],[a sin^(2)theta+b cos^(2)theta=c rArr tan^(2)theta=],[" 1) "(b-c)/(a-c)quad " 2) "(c-b)/(a-c)quad " 3) "(a-c)/(b-c)]

a sin^(2)theta+b cos^(2)theta=c then tan^(2)theta

If a sin^(2)theta+b cos^(2)theta=c then tan^(2)theta=

a sin^(2) theta + b cos^(2) theta =c implies tan^(2) theta =

a sin^(2) theta + b cos^(2) theta =c implies tan^(2) theta =

If asin^(2)theta+bcos^(2)theta=c , then prove that tan^(2)theta=(c-b)/(a-c)

If asin^(2)theta+bcos^(2)theta=c , then prove that tan^(2)theta=(c-b)/(a-c)

If asin^2 theta +bcos^2 theta =c .Show that tan^2 theta =(c-b)/(a-c)

cos theta+cos^(2)theta=1,a sin^(12)theta+b sin^(10)theta+c sin^(8)theta+d sin^(6)theta=1rArr(b+c)/(a+d)=

If : asec^(2) theta - b * tan^(2) theta = c,"then" = sin theta = A) sqrt((a +c)/(b + c) B) sqrt((a -c)/(b - c) C) sqrt((a -c)/(b + c) D) sqrt((a + c)/(b - c)

c(1+cos2theta)= (A) c 2sin^2theta (B) c2cos^2theta (C) c2tan^2theta (D) none of these