[" The equation of a wave on a string of linear mass density "],[0.04kgm^(-1)" is given by "],[y=0.02(m)sin[2 pi((t)/(0.04(s))-(x)/(0.50(m)))]],[" The tension in the string is "]

The equation of a wave on a string of linear mass density 0.04 kgm^(-1) is given by y = 0.02(m) sin[2pi((t)/(0.04(s)) -(x)/(0.50(m)))] . Then tension in the string is

The equation of a wave on a string of linear mass density 0.04 kgm^(-1) is given by y = 0.02(m) sin[2pi((t)/(0.04(s)) -(x)/(0.50(m)))] . Then tension in the string is

the equation of a wave on a string of linear mass density 0.04 kgm^(-1) is given by y = 0.02(m) sin[2pi((t)/(0.04(s)) -(x)/(0.50(m)))] . Then tension in the string is

The equation of a wave on a string of linear mass density 0.04 kg m^(-1) is given by y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))] . The tension in the string is :

The equation of a wave on a string of linear mass density 0.04 kg m^(-1) is given by y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))] . The tension in the string is :

The equation of a transverse wave along a stretched string is given by y = 15 sin 2pi ((t)/(0.04) - (x)/(40)) cm . The velocity of the wave is

The equation of a transverse wave propagating through a stretched string is given by y=2 sin 2pi ((t)/(0.04) -x/(40)) where y and x are in centimeter and t in seconds. Find the velocity of the wave, maximum velocity of the string and the maximum acceleration.

The transverse displacement of a string of a linear dinsity 0 . 0 1kgm^(-1) , clamped at its ends is given by Y _(x,t)= 0 . 0 3 sin((2pi x)/(3)) cos (60 pi t) , where x and y arein metres and time t is in seconds . Tension in the string is