The distance of the point (1,3,-7) from ...

The distance of the point `(1,3,-7)` from the plane passing through the point `(1,-1,-1),` having normal perpendicular to both the lines `(x-1)/1=(y+2)/(-2)=(z-4)/3a n d(x-2)/2=(y+1)/(-1)=(z+7)/(-1)i s:` `5/(sqrt(83))` (2) `(10)/(sqrt(74))` (3) `(20)/(sqrt(74))` (4) `(10)/(sqrt(83))`

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The distance of the point (1,3,-7) from the plane passing through the point (1,-1,-1), having normal perpendicular to both the lines (x-1)/1=(y+2)/(-2)=(z-4)/3a n d(x-2)/2=(y+1)/(-1)=(z+7)/(-1) is

The distance of the point (1, 3, -7) from the plane passing through the point (1, -1, -1) having normal perpendicular to both the lines (x-1)/(1)=(y+2)/(-2)=(z-4)/(3) and (x-2)/(2)=(y+1)/(-1)=(z+7)/(-1) is

The distance of the point (1,3,-7) from the plane passing through the point (1,-1,-1) , having normal perpendicular to both the lines (x-1)/(1)=(y+2)/(-2)=(z-4)/(3) and (x-2)/(2)=(y+1)/(-1)=(z+7)/(-1) is (5)/(sqrt(83)) (2) (10)/(sqrt(74)) (3) (20)/(sqrt(74)) (4) (10)/(sqrt(83))

Find the distance of the point (1,1,1) from the plane passing through the point (-1, -2, -1) and whose normal is perpendicular to both the lines. (x+1)/(3)=(y+2)/(1)= (z+1)/(2) and (x-2)/(1)= (y+2)/(2)= (z-3)/(3)

The distance of the point (1,-2,4) from the plane passing through the point (1,2,2) perpendicular to the planes x-y+2z=3 and 2x-2y+z+12=0 is

The distance of the point `(1,3,-7)` from the plane passing through the point `(1,-1,-1),` having normal perpendicular to both the lines `(x-1)/1=(y+2)/(-2)=(z-4)/3a n d(x-2)/2=(y+1)/(-1)=(z+7)/(-1)i s:` `5/(sqrt(83))` (2) `(10)/(sqrt(74))` (3) `(20)/(sqrt(74))` (4) `(10)/(sqrt(83))`

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