[" Qn 19.A point source of electromagnetic radiation has an average power "],[" output of "800W" .The maximum value of electric field at a distance of "4.0],[" m from the source is: "],[" (a) "54.77V/m],[" (b) "57.8V/m],[" (b) "64.7V/m],[" (d) "56.72V/m]

A point source of electromagnetic radiation has an average power output of 800 W . The maximum value of elecvtric field at a distance 4.0 m from the source is

A point source of electromagnetic radiation has an average power output of1500W. The maximum value of electric field at a distance 3m from this source in Vm^-1 is

A point source, of electromagnetic radiation has average power output of 800 W. The maximum value electric at a distance 4.0 m from the source is:

A point source of electromagnetic rediation has an average power output of 960 W. The peak value of the electric field at a distance 400 cm from the source is

A point source of electromagnetic radiation has an average power output of 800W. The mximum value of electric field at a distance 3.5 m from the source will be 62.6 V/m, the maximum value of magnetic field will be -

A point source of electromagnetic radiation has an average power output of 800W . The maximum value of electric field at a distance 3.5m from the source will be 62.6 V/m , the energy density at a distance 3.5 m from the source will be- (in "joule"//m^(3) )

A point source of electromagnetic radiation has an average power output of 800W. (a) Find the maximum value of electric field at a distance 3.5 m from the source. (b) What will be the maximum value of magnetic field? (c) What will be the energy density at a distance at a distance 3.5m from the source?