(1)/(x+4)-(1)/(x-7)=(11)/(30)

Solve the inequality,(1)/(x-1)-(4)/(x-2)+(4)/(x-3)-(1)/(x-4)<(1)/(30)

Solve: (1)/((x+3))+(1)/((2x-1))=(11)/((7x+9)),xne-3,(1)/(2),(-9)/(7).

Simplify :((-7)/(18)x(15)/(-7))-(1x(1)/(4))+((1)/(2)x(1)/(4))

Solve: (x)/(30)-(1)/(33)=(x)/(11)-(7)/(22)

(1)/(1.23)+(1)/(2.3.4)+(1)/(3.4.5)+(1)/(4.5.6)= a) (7)/(30) b) (11)/(30) c) (13)/(30) d (17)/(30)

If x:y=1:1, then (3x+4y)/(5x+6y)=(7)/(11) (b) (17)/(11)(17)/(23)(d)(4)/(5)

Let f(x)=int(x^(2)dx)/((1+x^(2))(1+sqrt(x^(2)+1))) and f(0)=0 Then value of f(1) will be (7)/(11)(tan(theta)/(2))_((11)/(7))^((11)/(7))+C (b) (7)/(11)((cos theta)/(2))^((11)/(7))+C(7)/(11)(s int h(eta)/(2))^((11)/(7))+C (d)none of these

The range of the function f(x)=(x^(2)+x+2)/(x^(2)+x+1),x in R, is (1,oo)(b)(1,(11)/(7))(1,(7)/(3)) (d) (1,(7)/(5))

Solve : -4 = -7 + 3x . A. -1 B. 1 C. (11)/(3) D. (-11)/(3)

3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11;x!=(3)/(5),-(1)/(7)