int(tan x-tan alpha)/(tan x+tan alpha)dx

Let alpha in (0, pi/2) be fixed. If the integral int(tan x + tan alpha)/(tan x - tan alpha)dx = A(x)cos 2 alpha+B(x) sin 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

Let alpha in (0, pi//2) be fixed. If the integral int("tan x" + "tan" alpha)/("tan x" - "tan" alpha)dx = A(x)"cos 2 alpha+B(x) "sin" 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

Let alpha in (0, pi//2) be fixed. If the integral int("tan x" + "tan" alpha)/("tan x" - "tan" alpha)dx = A(x)"cos 2 alpha+B(x) "sin" 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.

If sin(x+3 alpha)=,3sin(alpha-x) then (A) tan x,=tan alpha (B) tan x,=tan^(2)alpha (C) tan x,=tan^(3)alpha (D) tan x,=3tan alpha

int (tan x-tan x//2)/(1+ tan x tan x//2)dx=

int tan(x-alpha).tan(x+alpha).tan 2x dx is equal to

int tan(x-alpha).tan(x+alpha).tan 2x dx is equal to

If int tan(x-alpha)tan(x+alpha)*tan2xdx=plog|sec2x|+qlog|sec(x+alpha)|+rlog|sec(x-alpha)|+c then p+q+r= . . ..

If alpha=(2 pi)/(7), then tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha