[" 18."(sqrt(27)-(9)/(sqrt(3))-sqrt((1)/(9))+sqrt((1)/(27)))=(1)/(1199)" ami "],[[" (1) "sqrt(3)," (ii) "2sqrt(3)," (iii) "0," (ii) "3sqrt(3)]]

sqrt(27)-(9)/(sqrt(3))-root(4)((1)/(9))+root(6)((1)/(27))

(sqrt(3)+1)(1-sqrt(12))+(9)/(sqrt(3)+sqrt(12))

27^(1(1)/(3))times sqrt((1)/(9))-:81^((-1)/(4))=?

a=9-4sqrt(5),sqrt(a)-(1)/(sqrt(a))=?

sqrt(((3)/(7))^(x+1))=(343)/(27

(sqrt(9))^(2)xx(sqrt(81))^(5)div(27)^(2)=9^(?)

a=9-4sqrt(5) , sqrt(a)-1/sqrt(a)=?

Prove that (i) (1)/(3+sqrt(7)) + (1)/(sqrt(7)+sqrt(5))+(1)/(sqrt(5)+sqrt(3)) +(1)/(sqrt(3)+1)=1 (ii) (1)/(1+sqrt(2))+(1)/(sqrt(2)+sqrt(3))+(1)/(sqrt(3)+sqrt(4))+(1)/(sqrt(4)+sqrt(5))+(1)/(sqrt(5)+sqrt(6))+(1)/(sqrt(6)+sqrt(7)) +(1)/(sqrt(7)+sqrt(8))+(1)/(sqrt(8) + sqrt(9)) = 2