The curve `xy = c(c > 0)` and the circle `x^2 +y^2=1` touch at two points, then distance between the points of contact is

The curve x y=c ,(c >0), and the circle x^2+y^2=1 touch at two points. Then the distance between the point of contacts is 1 (b) 2 (c) 2sqrt(2) (d) none of these

The curve xy=c,(c>0), and the circle x^(2)+y^(2)=1 touch at two points.Then the distance between the point of contacts is 1 (b) 2(c)2sqrt(2)quad (d) none of these

Prove that the circle x^2 + y^2 -6y + 4 = 0 and the parabola y^(2) = x touch. Find the common tangent at the point of contact.

If x = 7 touches the circle x^2 + y^2 - 4x - y - 12 =0 , then the co-ordinates of the point of contact are :

If the line y=mx+asqrt(1+m^2) touches the circle x^2+y^2=a^2 , then the point of contact is

If the tangent to the parabola y= x^(2) + 6 at the point (1, 7) also touches the circle x^(2) + y^(2) + 16x + 12y + c =0 , then the coordinates of the point of contact are-

If the line x=7 touches the circle x^2+y^2-4x-6y-12=0 , then the co-ordinates of the point of contact are