[" 1.If "A=[[1,sin theta,1],[-sin theta,1,sin theta],[-1,-sin theta,1]];" then for all "theta in((3 pi)/(4),(5 pi)/(4))],[det(A)" lies in the interval "]

If A= [{:(1, "sin"theta,1), (-"sin"theta, 1, "sin" theta),(-1, -"sin"theta, 1):}], " then for all "theta in ((3pi)/(4), (5pi)/(4)) det (A) lies in the interval

If A= [{:(1, "sin"theta,1), (-"sin"theta, 1, "sin" theta),(-1, -"sin"theta, 1):}], " then for all "theta in ((3pi)/(4), (5pi)/(4)) det (A) lies in the interval

let Delta=det[[1,sin theta,1-sin theta,1,sin theta-1,-sin theta,1]],0<=theta<=2 pi

Let A=[[1,sin theta,1-sin theta,1,sin theta-1,-sin theta,1]],theta varepsilon((3 pi)/(4),(5 pi)/(4)) then |A| lies in (A),[(1)/(2),3)(B)[1,4)(C)[-1,2](D) none of these

If Delta=|(1, sin theta, 1 ),(-sin theta, 1, sin theta),(-1 , -sin theta, 1)| then Delta lies in the interval

Let A={:[( 1,sin theta , 1),( -sin theta , 1, sin theta ),( -1 ,-sin theta , 1 )]:} ,"where" 0 letheta le 2pi , Then

Let A={:[( 1,sin theta , 1),( -sin theta , 1, sin theta ),( -1 ,-sin theta , 1 )]:} ,"where" 0 letheta le 2pi , Then