int_(0)^( pi)x log sin xdx=

Evaluate int_0^(pi/2) log sin xdx

int_(0)^( pi)log xdx

int_(0)^( pi/2)x sin xdx

int x log sin xdx

"int_(0)^( pi)x sin^(2)xdx

int_(0)^( pi)x sin^(-1)xdx

If f:[0,pi]rarr R is continuous and int_(0)^( pi)f(x)sin xdx=int_(0)^( pi)f(x)cos xdx=0 then the number of roots of f(x) in (0,pi) is ...

valuate the following integrals: int_(0)^( pi)x sin^(2)xdx

int_(0)^( pi)x sin^(3)xdx

int_(0)^((pi)/(2))log sin xdx=int_(0)^((pi)/(2))log cos xdx=(1)/(2)(pi)log((1)/(2))