" The point of tangency of the circles "x^(2)+y^(2)-2x-4y=0" and "x^(2)+y^(2)-8y-4=0

The circles x^(2)+y^(2)-2x-4y+1=0 and x^(2)+y^(2)+4y-1 =0

Two circles x^(2) + y^(2) - 2x - 4y = 0 and x^(2) + y^(2) - 8y - 4 = 0

The equation of the circle passing through the point of intersection of the circles x^(2)+y^(2)-4x-2y=8 and x^(2)+y^(2)-2x-4y=8 and (-1,4) is (a)x^(2)+y^(2)+4x+4y-8=0(b)x^(2)+y^(2)-3x+4y+8=0(c)x^(2)+y^(2)+x+y=0(d)x^(2)+y^(2)-3x-3y-8=0

The number of common tangents to the circle x^(2)+y^(2)-2x-4y-4=0 and x^(2)+y^(2)+4x+8y-5=0 is _________.

The number of common tangents to the circle x^(2)+y^(2)-2x-4y-4=0 and x^(2)+y^(2)+4x+8y-5=0 is _________.

The circles x^(2)+y^(2)-12x+8y+48=0, x^(2)+y^(2)-4x+2y-4=0 are

The circles x^(2)+y^(2)-12x+8y+48=0, x^(2)+y^(2)-4x+2y-4=0 are

Find the equation of the circle through the points of interrection of the circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+6x+4y-12=0 and cutting the circle x^(2)+y^(2)-2x-4=0 orthogonally.

The point lying on common tangent to the circles x^(2)+y^(2)=4 and x^(2)+y^(2)+6x+8y-24=0 is