" (7) "sin^(2)n theta-sin^(2)(n-1)0=sin^(2)theta

sin^(2)n theta-sin^(2)(n-1)theta=sin^(2)theta where n is constant and n!=0,1

Solve the equation sin^(2)ntheta - sin^(2)(n-1)theta = sin^(2)theta

Solve the equation sin^(2)ntheta - sin^(2)(n-1)theta = sin^(2)theta

sin^2 n theta- sin^2 (n-1)theta= sin^2 theta where n is constant and n != 0,1

sin^2 n theta- sin^2 (n-1)theta= sin^2 theta where n is constant and n != 0,1

Prove that sin^(2)theta+sin^(2)2 theta+sin^(2)3 theta+....+sin^(2)n theta=(n)/(2)-(sin n theta cos(n+1)theta)/(2sin theta)

Prove that sin theta+sin3 theta+sin5 theta+....+sin(2n-1)theta=(sin^(2)n theta)/(sin theta)

The value of I(n)=int_(0)^( pi)(sin^(2)n theta)/(sin^(2)theta)d theta is (AA n in N)

If P_(n)=cos^(n)theta+sin^(n)theta and Q_(n)=cos^(n)theta-sin^(n)theta then show that p_(n-2)=-sin^(2)theta cos^(2) theta p_(n-4) hence show that p_(4)=1-2 sin^(2) theta cos^(2) theta Q_(4)=cos^(2) theta- sin^(2) theta