64.sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)

"(i) "sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta

Prove that sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta

Prove that sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta .

Prove that (sin^(4)theta-cos^(4)theta)/(sin^(2)theta-cos^(2)theta)=1

sin^(4)theta+cos^(4)theta=1-2sin^(2)theta cos^(2)theta

If : sin^(4)theta+cos^(4)theta+sin^(2)theta*cos^(2)theta=1-u^(2), "then" : u=

Find the value of 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)-(sin^(2)theta+cos^(2)theta)^(2)

Evaluate : 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+4(sin^(2)theta+cos^(2)theta)

The value of (2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta))/(cos^(4)theta-sin^(4)theta-2cos^(2)theta) is :