" Given that "1^(2)+2^(2)+3^(2)+....+10^(2)=385

Given that 1^(2) + 2^(2) + 3^(2) + …. + n^(2) = (n)/(6) (n + 1) (2n + 1) , then 10^(2) + 11^(2) + 12^(2) + … + 20^(2) is equal to

P(n) : 1^(2) + 2^(2) + 3^(2) + .......+ n^(2) = n/6(n+1) (2n+1) n in N is true then 1^(2) +2^(2) +3^(2) + ........ + 10^(2) = .......

1^(2) + 2^(2) + 3^(2) + …+ 10^(2) is :

Given that 1^(2)+2^(2)+3^(2)+dot backslash+10^(2)=385,backslash then find the value of 2^(2)+4^(2)+6^(2)+backslash backslash+20^(2)

If 1^(2) + 2^(2) + 3^(3)+ 4^(2) + …….. + 10^(2) = 385 then find the value of 2^(2) + 4^(2) + 6^(2) + ………. + 20^(2)

Find the value of 1^2 + 2^2 + 3^2+.......+10^2

Divide the given polynomial by the given monomial 10 (a^(3) b^(2) c^(2) - a^(2) b^(3) c^(2) + a^(2) b^(2) c^(3)) div 2abc

(1^(2) + 2^(2) + 3^(2) + …. + 10^(2)) is equal to

1^2+2^2+3^2+4^4+...........10^2 =?

At 27^(@) C and 37^(@) C , the specific rates of a reaction are given as 1.62 xx 10^(-2) s^(-1) and 3.2 xx 10^(-2) s^(-1) . Calculate the energy of activation for the given reaction.