(k,0),(4,0),(0,2)

Find the value of k, if the area of triangle is 4 square unit and vertices are P(k,0),Q(4,0),R(0,2)

If the points (0,0),(2,0),(0,4),(1,k) are concyclic then k^(2)-4k=

The four distinct points (0,0),(2,0),(0,-2) and (k,-2) are conclyic if k=

If the points (0,0),(2,0),(0,-2) and (k,-2) are concylic then k=

If the points (0,0),(2,0),(0,-2) and (k,-2) are concyclic then k is

If the points (0,0),(2,0),(0,-2) and (k,-2) are concylic then k=

Find the value of k,if area of triangle is 4 sq. units and vertices arw (k,0),(4,0) and(0,2) using determinant.

If the points (2,3),(0,2),(4,5),(0,k),(k!=2) are concyclic then k=

Find the values of 'k' if area of the triangle is 4 square unts and vertices are (2,0),(0,4),(0,k) .

The points (1,0),(0,1),(0,0) and (2k,3k),k!=0 are concyclic if k =