[" Vapour pressure of pure water at "298K" is "23.8mm" Hg."50g" of urea "],[(NH_(2)CONH_(2))" is dissolved in "850g" of water.Calculate the vapour pressure "],[" of water for this solution and its relative lowering."]

Vapour pressure of pure water at 298 K is 23.8 mm Hg . 50g of urea (NH_(2)CONH_(2)) is dissolved in 850g of water. Calculate the vapour pressure of water for this solution and its relative lowering.

Vapour pressure of pure water at 298 K is 23.8 mm Hg . 50g of urea (NH_(2)CONH_(2)) is dissolved in 850g of water. Calculate the vapour pressure of water for this solution and its relative lowering.

Vapour pressure of pure water at 298 K is 23.8 mm Hg . 50g of urea (NH_(2)CONH_(2)) is dissolved in 850g of water. Calculate the vapour pressure of water for this solution and its relative lowering.

Vapour pressure of pure water at 298 K is 23.8 mm Hg. 50 g of urea (NH_(2) CONH_(2)) is dissolved is 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering.

Vapour pressure of pure water at 298K is 23.8 mm Hg. 50g of urea (NH_2CONH_2) is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering.

Vapour pressure of pure water at 298 K is 23.8 mm Hg. 50g urea (NH_(2)CONH_(2)) is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering. Consider Raoult's law and formula for relative lowering in vapour pressure, (P_(A)^(0)-P_(s))/(P_(A)^(0))=(n_(B))/(n_(A))=(W_(B))/(M_(B))xx(M_(A))/(W_(A)) Where, (P_(A)^(0)-P_(s))/(P_(A)^(0)) is called relative lowering in vapour pressure.