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The axis of symmetry of the conic y = a...

The axis of symmetry of the conic `y = ax^2 + bx + c` is

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The ratio of the roots of the equation ax^(2)+bx+c=0 is same equation Ax^(2)+Bx+C=0. If D_(1) and D_(2) are the discriminants of 0. If D_(1) and D_(2) are the ax^(2)+bx+C=0 and Ax^(2)+Bx+C=0 respectively,then D_(1):D_(2)

The axis of symmetry may or may not, overlap the Y-axis, which depends on the quadratic function. But axis of symmetry is always parallel to Y-axis.

y= ax + bx^(2)