If angle `theta` is divided into two parts such that the tangents of one part is `lambda` times the tangent of other, and `phi` is their difference, then show that `sintheta=(lambda+1)/(lambda-1)sinphi` .

If angle theta is divided into two parts such that the tangents of one part is lambda xx the tangent of other,and phi is their difference,then show that sin theta=(lambda+1)/(lambda-1)sin phi

If the angle theta be divided into two parts such that the tangent of one part is m times the tangent of the other, then prove that their difference phi is obtained fron the relation is sin phi=abs(((m-1))/((m+1)))sin theta

An angle theta is divided into two parts so that the ratio of the tangents of the parts is k, if the difference, sin phi = (k-1)/(k+1) sin theta

If an angle alpha be divided into two parts such that the ratio of tangents of the parts is K. If x be the difference between the two parts , then prove that sinx = (K-1)/(K+1) sin alpha .

If an angle alpha be divided into two parts such that the ratio of tangents of the parts is K. If x be the difference between the two parts , then prove that sinx = (K-1)/(K+1) sin alpha .

A positive acute angle is divided into two parts whose tangents are 1/2 and 1/3 . Then the angle is

A positive acute angle is divided into two parts whose tangents are 1/2 and 1/3. Then the angle is

A positive acute angle is divided into two parts whose tangents are (1)/(8)and(7)/(9) . What is the value of this angle ?

Divide Rs 98 into two such that one part of 6 times to the other part

A positive acute angle is divided into two parts whose tangents are 1/2 and 1/3. Show that the angle is (pi)/(4).