If `(tan(alpha+beta-gamma))/("tan"(alpha-beta+gamma))=(tangamma)/(tanbeta),(beta!=gamma)` then `sin2alpha+sin2beta+sin2gamma=` (a)`0` (b)` 1` (c) `2 `(d)`1/2`

If (tan(alpha+beta-gamma))/(tan(alpha-beta+gamma))=(tan gamma)/(tan beta),(beta!=gamma) then sin2 alpha+sin2 beta+sin2 gamma=(a)0(b)1(c)2(d)(1)/(2)

If (tan(alpha + beta - gamma))/(tan(alpha - beta + gamma)) = (tan gamma)/(tan beta), (beta ne gamma) , then sin 2alpha + sin 2beta + sin 2gamma=

If (tan (alpha- beta+ gamma))/(tan (alpha+ beta- gamma))=(tan beta)/( tan gamma) , show that either sin (beta- gamma)=0 or sin 2 alpha+ sin 2 beta+ sin 2 gamma=0

If (tan(alpha +beta - gamma))/(tan(alpha -beta + gamma)) = (tan gamma/tan beta) show that sin(beta -gamma) =0 or sin(beta -gamma) =0 , or sin2 alpha +sin2 beta + sin2 gamma =0

If tan beta=(tan alpha+tan gamma)/(1+tan alpha tan gamma)* prove that sin2 beta=(sin2 alpha+sin2 gamma)/(1+sin2 alpha sin2 gamma)

sin(beta+gamma-alpha)+sin(gamma+alpha-beta)+sin(alpha+beta-gamma)-sin(alpha+beta+gamma)=

If 2 sin alphacos beta sin gamma=sinbeta sin(alpha+gamma),then tan alpha,tan beta and tan gamma are in

If cos alpha+cos beta+cos gamma=0 & sin alpha +sin beta +sin gamma=0 . Then Prove that sin2alpha+sin2beta+sin2gamma=0

If 2 sin alphacos beta sin gamma=sinbeta sin(alpha+gamma),then tan alpha,tan beta and gamma are in

If 2 sin alphacos beta sin gamma=sinbeta sin(alpha+gamma),then tan alpha,tan beta and gamma are in